Integrand size = 31, antiderivative size = 112 \[ \int (b \cos (c+d x))^{4/3} (A+B \cos (c+d x)) \sec ^2(c+d x) \, dx=-\frac {3 A b \sqrt [3]{b \cos (c+d x)} \operatorname {Hypergeometric2F1}\left (\frac {1}{6},\frac {1}{2},\frac {7}{6},\cos ^2(c+d x)\right ) \sin (c+d x)}{d \sqrt {\sin ^2(c+d x)}}-\frac {3 B (b \cos (c+d x))^{4/3} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2}{3},\frac {5}{3},\cos ^2(c+d x)\right ) \sin (c+d x)}{4 d \sqrt {\sin ^2(c+d x)}} \]
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Time = 0.12 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.097, Rules used = {16, 2827, 2722} \[ \int (b \cos (c+d x))^{4/3} (A+B \cos (c+d x)) \sec ^2(c+d x) \, dx=-\frac {3 A b \sin (c+d x) \sqrt [3]{b \cos (c+d x)} \operatorname {Hypergeometric2F1}\left (\frac {1}{6},\frac {1}{2},\frac {7}{6},\cos ^2(c+d x)\right )}{d \sqrt {\sin ^2(c+d x)}}-\frac {3 B \sin (c+d x) (b \cos (c+d x))^{4/3} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2}{3},\frac {5}{3},\cos ^2(c+d x)\right )}{4 d \sqrt {\sin ^2(c+d x)}} \]
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Rule 16
Rule 2722
Rule 2827
Rubi steps \begin{align*} \text {integral}& = b^2 \int \frac {A+B \cos (c+d x)}{(b \cos (c+d x))^{2/3}} \, dx \\ & = \left (A b^2\right ) \int \frac {1}{(b \cos (c+d x))^{2/3}} \, dx+(b B) \int \sqrt [3]{b \cos (c+d x)} \, dx \\ & = -\frac {3 A b \sqrt [3]{b \cos (c+d x)} \operatorname {Hypergeometric2F1}\left (\frac {1}{6},\frac {1}{2},\frac {7}{6},\cos ^2(c+d x)\right ) \sin (c+d x)}{d \sqrt {\sin ^2(c+d x)}}-\frac {3 B (b \cos (c+d x))^{4/3} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2}{3},\frac {5}{3},\cos ^2(c+d x)\right ) \sin (c+d x)}{4 d \sqrt {\sin ^2(c+d x)}} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.79 \[ \int (b \cos (c+d x))^{4/3} (A+B \cos (c+d x)) \sec ^2(c+d x) \, dx=-\frac {3 b^2 \cot (c+d x) \left (4 A \operatorname {Hypergeometric2F1}\left (\frac {1}{6},\frac {1}{2},\frac {7}{6},\cos ^2(c+d x)\right )+B \cos (c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2}{3},\frac {5}{3},\cos ^2(c+d x)\right )\right ) \sqrt {\sin ^2(c+d x)}}{4 d (b \cos (c+d x))^{2/3}} \]
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\[\int \left (\cos \left (d x +c \right ) b \right )^{\frac {4}{3}} \left (A +B \cos \left (d x +c \right )\right ) \left (\sec ^{2}\left (d x +c \right )\right )d x\]
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\[ \int (b \cos (c+d x))^{4/3} (A+B \cos (c+d x)) \sec ^2(c+d x) \, dx=\int { {\left (B \cos \left (d x + c\right ) + A\right )} \left (b \cos \left (d x + c\right )\right )^{\frac {4}{3}} \sec \left (d x + c\right )^{2} \,d x } \]
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Timed out. \[ \int (b \cos (c+d x))^{4/3} (A+B \cos (c+d x)) \sec ^2(c+d x) \, dx=\text {Timed out} \]
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\[ \int (b \cos (c+d x))^{4/3} (A+B \cos (c+d x)) \sec ^2(c+d x) \, dx=\int { {\left (B \cos \left (d x + c\right ) + A\right )} \left (b \cos \left (d x + c\right )\right )^{\frac {4}{3}} \sec \left (d x + c\right )^{2} \,d x } \]
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\[ \int (b \cos (c+d x))^{4/3} (A+B \cos (c+d x)) \sec ^2(c+d x) \, dx=\int { {\left (B \cos \left (d x + c\right ) + A\right )} \left (b \cos \left (d x + c\right )\right )^{\frac {4}{3}} \sec \left (d x + c\right )^{2} \,d x } \]
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Timed out. \[ \int (b \cos (c+d x))^{4/3} (A+B \cos (c+d x)) \sec ^2(c+d x) \, dx=\int \frac {{\left (b\,\cos \left (c+d\,x\right )\right )}^{4/3}\,\left (A+B\,\cos \left (c+d\,x\right )\right )}{{\cos \left (c+d\,x\right )}^2} \,d x \]
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